60x^2-50x-40=0

Solution for 60x^2-50x-40=0 equation:

60x^2-50x-40=0

a = 60; b = -50; c = -40;
Δ = b2-4ac
Δ = -502-4·60·(-40)
Δ = 12100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12100}=110$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-110}{2*60}=\frac{-60}{120}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+110}{2*60}=\frac{160}{120}
=1+1/3
$